High-Index Lens Materials, Edge Thinning Physics & Chromatic Abbe Optimization • 13 min read

Calculating Lens Edge Thickness for High Minus Prescriptions: The Sagittal Depth Formula

EXECUTIVE CLINICAL SUMMARY
For wearers with moderate to high myopia (-4.00 D to -12.00 D), the most dreaded outcome when picking up new spectacles is discovering unsightly, thick edges protruding conspicuously past the frame rim. Patients frequently ask opticians: 'Exactly how thick will my lenses be if I choose a 1.60 vs. a 1.67 vs. a 1.74 index?' Unfortunately, many optical salespeople guess blindly. In ophthalmic physics, edge thickness is not a mystery—it is governed by rigorous geometrical mathematics through the Sagittal Depth (Sagitta) Formula. By calculating the radius of curvature from the lensmaker's equation and accounting for frame aperture diameter and decentration, exact millimeter edge thicknesses can be predicted before a blank is even blocked. We unpack the mathematics of lens thinning.
ELLASUV Clinical Metrology Laboratory Ophthalmic Laboratory Surfacing & Geometrical Optics Division
ISO 8980-3 / ANSI Z80.1 Metrology Updated: 2026-09-07 ✓ Peer-Reviewed

The Approximate & Exact Sagittal Depth Formulas

The sagittal depth (ss) represents the perpendicular distance from the vertex of a spherical curve to the chord joining its edges. For an optical lens with semi-diameter yy (half of the lens diameter, y=d/2y = d/2) and radius of curvature rr:

Exact Sagitta Formula: s=rr2y2\text{Exact Sagitta Formula: } s = r - \sqrt{r^2 - y^2}

Approximate Sagitta Formula: sy22r=y2×F2000(n1)\text{Approximate Sagitta Formula: } s \approx \frac{y^2}{2r} = \frac{y^2 \times F}{2000(n - 1)}

Where FF is surface dioptric power in diopters, yy is semi-diameter in millimeters, and nn is refractive index of the monomer material. For a minus lens, total edge thickness (tet_e) is equal to center thickness (tct_c) plus the sagittal depth of the back surface minus the front surface:

te=tc+(s2s1)t_e = t_c + (s_2 - s_1)

The Exponential Power of Frame Diameter (y2y^2)

Notice the quadratic variable y2y^2 in the numerator! Edge thickness increases with the square of the lens aperture radius.

  • In a small 46 mm eye size round frame (y=23 mmy = 23\ \text{mm}), y2=529y^2 = 529.
  • In a wide 56 mm eye size rectangular frame (y=28 mmy = 28\ \text{mm}), y2=784y^2 = 784.

Simply increasing frame width from 46 mm to 56 mm increases edge thickness by nearly 50%, completely obliterating any cosmetic gains achieved by paying for an expensive high-index material!

Index Comparison: -6.00D at 50mm Diameter

Consider a 6.00 D-6.00\ \text{D} prescription with a 1.0 mm1.0\ \text{mm} center thickness across common refractive indices:

  1. Standard CR-39 (n=1.50n = 1.50): te8.5 mmt_e \approx 8.5\ \text{mm} (Extremely thick, heavy rim overhang).
  2. Mid-Index 1.56: te7.7 mmt_e \approx 7.7\ \text{mm}.
  3. High-Index MR-8 (n=1.60n = 1.60): te6.0 mmt_e \approx 6.0\ \text{mm} (30% thinner, outstanding optical clarity).
  4. Ultra-High Index MR-7 (n=1.67n = 1.67): te5.3 mmt_e \approx 5.3\ \text{mm} (38% thinner).
  5. Extreme Index MR-174 (n=1.74n = 1.74): te4.7 mmt_e \approx 4.7\ \text{mm} (45% thinner).
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FREQUENTLY ASKED CLINICAL QUESTIONS

Expert Answers

How can I calculate how thick my glasses lenses will be?
Lens edge thickness depends on your prescription power, lens refractive index, and frame size. Using the Sagittal Depth formula (s=y2×F/[2000(n1)]s = y^2 \times F / [2000(n-1)]), smaller frames and higher refractive indices give much thinner edges.
What is the biggest factor in reducing lens thickness for high minus numbers?
Frame size! Because edge thickness scales with the square of frame diameter, choosing a small, round 46mm to 48mm frame reduces edge thickness more than upgrading from 1.60 to 1.74 index.
What is the thinnest lens material available for high myopia?
1.74 ultra-high-index plastic is the thinnest plastic lens available globally, reducing edge thickness by up to 45% compared to standard CR-39 plastic.
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